Breathing and Exchange of Gases Class 11 Question Answer | NCERT Biology Chapter 14 Solutions Skip to content
🪔 शुभ नवरात्रि! Navratri Mega Sale Up to 34% off every pack + extra 15% off on 2 or more Shop the sale
Smart Notes for Every Exam · instant PDF download after payment +91 88240 98091
Home › NCERT Solutions › Class 11 Biology › Chapter 14
NCERT Solutions · Class 11 Biology · Chapter 14

Chapter 14: Breathing and Exchange of Gases (Human Physiology)

Answers to all NCERT exercises of Chapter 14, Breathing and Exchange of Gases (NCERT Class 11 Biology, 2026-27): respiratory organs, mechanism of breathing, exchange and transport of gases and disorders. Each answer is written in full, the way it is expected in school and board exams. All 14 questions are answered, with the key answer highlighted.

NCERT textbook Chapter 14 (PDF)

Exam revision? Chapter 14 notes with key points, diagrams and practice questions: see the free sample · ₹199 for all 19 chapters

Free NCERT solutions by Notes Bazar · www.notesbazar.in/ncert-solutions/class-11-biology/chapter-14-breathing-and-exchange-of-gases

Exercises

1
Define vital capacity. What is its significance?
Solution

Vital capacity is the maximum volume of air a person can breathe in after a forced expiration (or breathe out after a forced inspiration): VC = ERV + TV + IRV (about 3500–4600 mL). Significance: it measures the maximum exchange of air in one breath and the strength of the respiratory muscles; it is higher in athletes and lower in lung diseases (asthma, emphysema, fibrosis), so it is used in the clinical assessment of lung function.

2
State the volume of air remaining in the lungs after a normal breathing.
Solution

After a normal expiration the lungs still hold the functional residual capacity: FRC = ERV + RV = (1000–1100) + (1100–1200) = about 2100–2300 mL.

3
Diffusion of gases occurs in the alveolar region only and not in other parts of the respiratory system. Why?
Solution

Only the alveoli have the features needed for diffusion: an extremely thin diffusion membrane (squamous alveolar epithelium, capillary endothelium and a thin basement substance; much less than a millimetre), a huge surface area, a rich network of blood capillaries, and a partial-pressure gradient between alveolar air and blood. The other parts (nose to terminal bronchioles) form the conducting part: their walls are thick, often supported by cartilage, and have no such capillary network; they only conduct, clean, warm and humidify the air.

4
What are the major transport mechanisms for CO₂? Explain.
Solution

(i) About 70% as bicarbonate: in tissues, where pCO₂ is high, CO₂ diffuses into RBCs and plasma; carbonic anhydrase (very high in RBCs) catalyses CO₂ + H₂O → H₂CO₃ → HCO₃⁻ + H⁺; at the alveoli, where pCO₂ is low, the reaction reverses and CO₂ is released. (ii) 20–25% bound to haemoglobin as carbamino-haemoglobin: binding is favoured by high pCO₂ and low pO₂ (tissues) and release by low pCO₂ and high pO₂ (alveoli). (iii) About 7% dissolved in plasma. Each 100 mL of deoxygenated blood delivers about 4 mL of CO₂ to the alveoli.

5
Compared with alveolar air, the pO₂ and pCO₂ of atmospheric air are: (i) pO₂ lesser, pCO₂ higher (ii) pO₂ higher, pCO₂ lesser (iii) both higher (iv) both lesser.
Solution

(ii): atmospheric pO₂ 159 mm Hg vs. 104 in alveoli (higher); pCO₂ 0.3 vs. 40 (lesser).

6
Explain the process of inspiration under normal conditions.
Solution

Inspiration occurs when the pressure inside the lungs falls below atmospheric pressure. (i) The diaphragm contracts and flattens, increasing the volume of the thoracic chamber in the antero-posterior axis. (ii) The external intercostal muscles contract, lifting the ribs and sternum and increasing the volume in the dorso-ventral axis. (iii) Because the thorax is air-tight, the increase in thoracic volume increases the pulmonary volume. (iv) This lowers the intra-pulmonary pressure below atmospheric pressure, so air from outside rushes into the lungs.

7
How is respiration regulated?
Solution

By the neural system. The respiratory rhythm centre in the medulla sets the rhythm. The pneumotaxic centre in the pons moderates it, shortening inspiration and so changing the rate. A chemosensitive area beside the rhythm centre is very sensitive to CO₂ and H⁺; when they rise it signals the rhythm centre to increase breathing so they are removed. Receptors in the aortic arch and carotid artery also detect CO₂ and H⁺ and signal the rhythm centre. The role of O₂ is insignificant.

8
What is the effect of pCO₂ on oxygen transport?
Solution

High pCO₂ (with high H⁺ and temperature) lowers the affinity of haemoglobin for O₂, shifting the oxygen dissociation curve to the right, so oxyhaemoglobin releases O₂ more easily: this happens in the tissues. Low pCO₂ in the alveoli favours the binding of O₂ to haemoglobin. So pCO₂ helps load O₂ in the lungs and unload it in the tissues.

9
What happens to the respiratory process in a man going up a hill?
Solution

At high altitude the atmospheric pressure and hence pO₂ are low, so less O₂ diffuses into the blood and haemoglobin is less saturated: the person feels breathless and the body gets less O₂ (hypoxia). In addition, climbing is exercise, raising CO₂ production. So the breathing rate and depth increase, and heart rate rises. On staying for some time the body acclimatises: more RBCs and haemoglobin are made (erythropoietin), helping to carry more O₂.

10
What is the site of gaseous exchange in an insect?
Solution

Insects have a tracheal system: air enters through spiracles and is carried by branching tracheal tubes to fine tracheoles, which reach the tissues; gas exchange takes place directly between the tracheoles and the body cells (blood does not carry O₂).

11
Define the oxygen dissociation curve. Can you suggest a reason for its sigmoid pattern?
Solution

The oxygen dissociation curve is the graph of the percentage saturation of haemoglobin with O₂ against the partial pressure of O₂. It is sigmoid because of cooperative binding: haemoglobin has four haem groups; binding of the first O₂ is difficult, but it changes the shape of the molecule so that the next O₂ molecules bind much more easily (steep middle part); when nearly all sites are filled, saturation levels off (plateau). This lets haemoglobin load O₂ fully in the lungs and release a lot at the lower pO₂ of tissues.

12
Have you heard about hypoxia? Gather information and discuss.
Solution

Hypoxia is a shortage of O₂ reaching the tissues. Types: (i) hypoxic (low pO₂ in air, e.g. high altitude: altitude sickness with breathlessness, headache, nausea); (ii) anaemic (too little haemoglobin, e.g. anaemia, or CO poisoning, which blocks haemoglobin); (iii) stagnant (poor blood flow, e.g. heart failure); (iv) histotoxic (cells cannot use O₂, e.g. cyanide poisoning). Prevention and treatment: gradual ascent and acclimatisation, oxygen cylinders for mountaineers and pilots, treating anaemia, avoiding smoke and CO.

13
Distinguish: (a) IRV and ERV (b) inspiratory and expiratory capacity (c) vital capacity and total lung capacity.
Solution

(a) IRV: additional air inspired by forcible inspiration (2500–3000 mL); ERV: additional air expired by forcible expiration (1000–1100 mL). (b) IC = TV + IRV: total air inspired after a normal expiration; EC = TV + ERV: total air expired after a normal inspiration. (c) VC = ERV + TV + IRV: maximum air breathed in after forced expiration; TLC = VC + RV: total air the lungs hold at the end of forced inspiration (includes the residual volume).

14
What is tidal volume? Find the approximate tidal volume of a healthy human in an hour.
Solution

Tidal volume is the volume of air inspired or expired in a normal breath: about 500 mL. At 12–16 breaths per minute: 500 × 12 = 6000 to 500 × 16 = 8000 mL per minute; in an hour, 6000 × 60 = 3,60,000 mL to 8000 × 60 = 4,80,000 mL, i.e. about 360–480 litres per hour.

Cover of Complete Biology Notes for Class 11 (NCERT 2026-27)
Done with the answers?Now revise the whole chapter: Class 11 Biology notes
  • For NCERT Biology Class 11 (2026-27 edition) - all 19 chapters
  • Typed concept notes with labelled diagrams for every topic
  • Every NCERT exercise question answered in full
₹199₹24920% off · all 19 chapters · instant PDF
Read free sample

What is inside the Chapter 14 notes →

Found a mistake or need help with a question? Message us on WhatsApp. Free study tips and new solutions: join our WhatsApp Channel.